Question

If 'n' represents total number of asymmetric carbon atoms in a compound, the possible number of optical isomers of the compound is

• A. 2n
• B. $n^2$
• C. $2^n$
• D. 2n + 2

Answer 1

Answer: (C)

$2^n$

Answer 2

For a molecule having $n$ asymmetric (chiral) carbon atoms, the maximum number of optical isomers that can be formed is given by

$$\text{Number of optical isomers} = 2^n.$$

Thus, the correct answer is (c) $2^n$.

A compound with $n$ chiral centers can form up to $2^n$ stereoisomers since each center can have two configurations (R or S).