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Question: 3.2 g of oxygen (At. wt. = 16) and 0.2 g of hydrogen (At. wt. = 1) are placed in a 1.12 litre flask ...

3.2 g of oxygen (At. wt. = 16) and 0.2 g of hydrogen (At. wt. = 1) are placed in a 1.12 litre flask at . The total pressure of the gas mixture will be

A

1 atm

B

4 atm

C

3 atm

D

2 atm

Answer

4 atm

Explanation

Solution

3.2 g O2=0.1 molO _ { 2 } = 0.1 \mathrm {~mol}, 0.2 gn=0.2 moln = 0.2 \mathrm {~mol},

P=nRTV=0.2×0.082×2731.12=4 atmP = \frac { n R T } { V } = \frac { 0.2 \times 0.082 \times 273 } { 1.12 } = 4 \mathrm {~atm}