Question

32.5 g of zinc (At. mass 65) will completely react with dilute sulphuric acid to give

• A. 1 mol of $H_2$
• B. 1/2 mol of $H_2$
• C. 2/3 mol of $H_2$
• D. Both 2/3 mol of 02 and 1/2 mol of $H_2$

Answer 1

Answer: (B)

1/2 mol of $H_2$

Answer 2

$\underset{\text{65 g}}{Zn}+H_{2}SO_{4} \to \underset{\text{1 mol}}{ZnSO_{4}}+H_{2}$ $\because$ $32\,g$ of $Zn$ wiil produce $H_{2}=1/2\,mol$