Question

The slope of graph drawn between stopping potential and frequency of incident light for a given surface will be :-

• A. h
• B. h/e
• C. eh
• D. e

Answer 1

Answer: (B)

h/e

Answer 2

The photoelectric equation is $h\nu = h\nu_0 + eV_0$. Rearranging this to express stopping potential ($V_0$) as a function of frequency ($\nu$) gives $V_0 = \left(\frac{h}{e}\right)\nu - \left(\frac{h\nu_0}{e}\right)$. Comparing this to the equation of a straight line $y = mx + c$, where $y = V_0$ and $x = \nu$, the slope $m$ is clearly $\frac{h}{e}$.