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Question: If concentration of [H+]ion in solution is (i) 10-3M (ii) 0.01 M (iii) 10-6M then pH of solution of...

If concentration of [H+]ion in solution is

(i) 10-3M (ii) 0.01 M (iii) 10-6M then pH of solution of (i), (ii) & (iii) are x, y and z respectively, then x + y + z will be:

Answer

11

Explanation

Solution

Given for each solution, pH is calculated using

pH=−log⁡[H+]\text{pH} = -\log[H^+]

  1. For (i) [H+]=10−3[H^+] = 10^{-3} M:

    pH=−log⁡(10−3)=3\text{pH} = -\log(10^{-3}) = 3

  2. For (ii) [H+]=0.01=10−2[H^+] = 0.01 = 10^{-2} M:

    pH=−log⁡(10−2)=2\text{pH} = -\log(10^{-2}) = 2

  3. For (iii) [H+]=10−6[H^+] = 10^{-6} M:

    pH=−log⁡(10−6)=6\text{pH} = -\log(10^{-6}) = 6

Sum: x+y+z=3+2+6=11x+y+z = 3+2+6 = 11