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Question: 300ml of a gas at \({{2}}{{{7}}^{{o}}}{{c}}\) is cooled to \({{ - }}{{{8}}^{{o}}}{{c}}\) at constant...

300ml of a gas at 27oc{{2}}{{{7}}^{{o}}}{{c}} is cooled to 8oc{{ - }}{{{8}}^{{o}}}{{c}} at constant pressure. The final volume is:
A) 150ml{{150ml}}
B) 300ml{{300ml}}
C) 265ml{{265ml}}
D) 380ml{{380ml}}

Explanation

Solution

Combined gas law is the combination of three laws i.e., Charles law, Boyle’s law, and Gay-Lussac’s law. Combined gas law shows that: Pressure is inversely proportional to the volume. Pressure is directly proportional to the temperature and The Volume is directly proportional to the measure of temperature.

Complete step by step answer:
Here we can follow Charles Law or simply we can follow combined gas law:
According to Charle’s law VαT{{V\alpha T}} at constant pressure
So we get V1V2=T1T2\dfrac{{{{{V}}_1}}}{{{{{V}}_2}}}{{ = }}\dfrac{{{{{T}}_1}}}{{{{{T}}_2}}} where the initial values are given by V1,T1{{{V}}_1}{{,}}{{{T}}_1}and final values are given by V2,T2{{{V}}_2}{{,}}{{{T}}_2}
Or
According to Combined Gas Law P1V1T1=P2V2T2\dfrac{{{{{P}}_1}{{{V}}_1}}}{{{{{T}}_1}}}{{ = }}\dfrac{{{{{P}}_2}{{{V}}_2}}}{{{{{T}}_2}}}
Since pressure is constant, P1=P2{{{P}}_1}{{ = }}{{{P}}_2}
So we get here, V1T1=V2T2\dfrac{{{{{V}}_1}}}{{{{{T}}_1}}}{{ = }}\dfrac{{{{{V}}_2}}}{{{{{T}}_2}}} where the initial values are given by V1,T1{{{V}}_1}{{,}}{{{T}}_1} and final values are given by V2,T2{{{V}}_2}{{,}}{{{T}}_2}.
Given: Initial volume V1=300ml{{{V}}_1}{{ = 300ml}}
Initial temperature, T1=27oC=27+273=300K{{{T}}_1}{{ = 2}}{{{7}}^{{o}}}{{C = 27 + 273 = 300 K}} (when we convert into kelvin i.e.,k{{k}})
Final volume, V2=?{{{V}}_2}{{ = ?}}
Final temperature, T2=8oC{{{T}}_2}{{ = - }}{{{8}}^{{o}}}{{C}}
=8+273=265K{{ = - 8 + 273 = 265K}}
Applying these values in the formula V1V2=T1T2\dfrac{{{{{V}}_1}}}{{{{{V}}_2}}}{{ = }}\dfrac{{{{{T}}_1}}}{{{{{T}}_2}}}we get,
300300=V2265\dfrac{{{{300}}}}{{{{300}}}}{{ = }}\dfrac{{{{{V}}_2}}}{{{{265}}}}
So, V2=300×265300=265{{{V}}_2}{{ = }}\dfrac{{{{300 \times 265}}}}{{{{300}}}}{{ = 265}}
The final volume is 265ml{{265ml}}.

So, the correct answer is Option C.

Additional Information:
Derivation of Combined Gas Law:
Boyle’s Law PV=K{{PV = K}},
Charles Law VT=K\dfrac{{{V}}}{{{T}}}{{ = K}},
and Gay- Lussac’s Law PT=K\dfrac{{{P}}}{{{T}}}{{ = K}}
Since Combined Gas Law is the combination of these three laws, the formula for combined gas law is PVT=K\dfrac{{{{PV}}}}{{{T}}}{{ = K}} where P{{P}} = pressure, T{{T}}= temperature, V{{V}} = volume and K{{K}} is constant.

Note: The temperature should always be in kelvin for the purpose of calculation. So, if the units are given in Celsius scale, it must be converted to kelvin by adding 273{ {273}} to a particular unit. We can adjust the formula of the Combined Gas Law to compare two different conditions in one substance.