Question

300 Joule of work is done in sliding up a 2 kg block on an inclined plane to a height of 10 metres. Taking value of acceleration due to gravity ‘g’ to be 10 m/s², work done against friction is

• A. 100 J
• B. 200 J
• C. 300 J
• D. Zero

Answer 1

Answer: (A)

100 J

Answer 2

Work done against gravity

$= m g h$

Work done against friction = (Total work done – work done against gravity)