Question
Question: 300 Joule of work is done in sliding a 2 kg. block up an inclined plane to a height of 10 meters. Ta...
300 Joule of work is done in sliding a 2 kg. block up an inclined plane to a height of 10 meters. Taking value of acceleration due to gravity ‘g’ to be 10 m/s2, work done against friction is
A
100 J
B
200 J
C
300 J
D
Zero
Answer
100 J
Explanation
Solution
Work done against gravity = mgh = 2 × 10 × 10 = 200J
Work done against friction = Total work done – Work done against gravity = 300 – 200 = 100J.