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Question

Physics Question on work, energy and power

300J300 \,J of work is done in sliding a 2kg2 \,kg block up an inclined plane of height 10m10\,m. The work done against friction is (Take g=10m/s2g=10\,m/{{s}^{2}} )

A

zero

B

100 J

C

200 J

D

300 J

Answer

100 J

Explanation

Solution

Given: Work done in sliding a block up an inclined plane W=320W = 320 Joule Mass of block M=2kgM = 2\, kg Height of inclined plane =10m= 10\, m The potential energy stored in the block is given by U=mgh=2×10×10=200JU=mgh=2\times 10\times 10=200\,J Hence, work done against friction is given by =WU=300200=100J=W-U=300-200=100\,J