Question
Physics Question on work, energy and power
300J of work is done in sliding a 2kg block up an inclined plane of height 10m. The work done against friction is (Take g=10m/s2 )
A
zero
B
100 J
C
200 J
D
300 J
Answer
100 J
Explanation
Solution
Given: Work done in sliding a block up an inclined plane W=320 Joule Mass of block M=2kg Height of inclined plane =10m The potential energy stored in the block is given by U=mgh=2×10×10=200J Hence, work done against friction is given by =W−U=300−200=100J