Question

300 cal of heat is supplied to raise the temperature of 50 g of air from $20{}^\circ C$ to $30{}^\circ C$ without any change in its volume. Change in internal energy per gram of air is

• A. zero
• B. 0.6 cal
• C. 1.2 cal
• D. 6.0 cal

Answer 1

Answer: (D)

6.0 cal

Answer 2

Given, $\Delta Q=300\,\,cal$ and $m=50\,\,g$ We know that $\Delta U=\Delta Q$ $\Delta U=300\,\,cal$ Change internal energy per gram $\Delta U=\frac{300}{50}=6\,\,cal$