Question

300 cal. of heat is given to a heat engine and it rejects 225 cal. of heat. If source temperature is 227°C, then the temperature of sink will be _______°C.

Answer 1

The correct answer is: 102

$n=\frac{W}{Q}=\frac{300-225}{300}$

$⇒T_L=\frac{3}{4} \space T_H=\frac{3}{4}(500)=375K$

⇒ $T_L = 102°C$