Question

3 V potentiometer used for the determination of internal resistance of a 2.4 V cell. The balance point of the cell in open circuit is 75.8 cm. When a resistor of$10.2 \Omega$ is used in the external circuit of the cell the balance point shifts to 68.3 cm length of the potentiometer wire. The internal resistance of the cell is

• A. $2.5 \Omega$
• B. $2.25 \Omega$
• C. $1.12 \Omega$
• D. $3.2$ $\Omega$

Answer 1

Answer: (C)

$1.12 \Omega$

Answer 2

: Internal resistance of cell

$1 _ { 2 } = 68.3 \mathrm {~cm}$