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Question: The Henry's law constant for oxygen is 1.3 x 10⁻³ mol dm⁻³ atm⁻¹. If partial pressure of oxygen is 0...

The Henry's law constant for oxygen is 1.3 x 10⁻³ mol dm⁻³ atm⁻¹. If partial pressure of oxygen is 0.46 atmosphere, what is the concentration of dissolved oxygen at 25°C and 1 atm pressure?

A

2.82 x 10⁻³ mol dm⁻³

B

5.98 x 10⁻⁴ mol dm⁻³

C

3.53 x 10⁻⁴ mol dm⁻³

D

5.98 mol dm⁻³

Answer

5.98 x 10⁻⁴ mol dm⁻³

Explanation

Solution

Henry’s law for a gas in solution is given by:

C = kH × p

where

kH = 1.3 × 10⁻³ mol dm⁻³ atm⁻¹ p = 0.46 atm

Substitute the values:

C = 1.3 × 10⁻³ × 0.46 = 5.98 × 10⁻⁴ mol dm⁻³.