Question

$3$ moles of a mono-atomic gas $(\gamma = 5/3)$ is mixed with $1$ mole of a diatomic gas $(\gamma = 7/5)$. The value of $?$ for the mixture will be

• A. 44815
• B. 44872
• C. 44902
• D. 15-Jul

Answer 1

Answer: (B)

44872

Answer 2

The number of degrees of freedom for the mixture is
$f_{\operatorname{mix}} =\frac{n_{1} f_{1}+n_{2} f_{2}}{n_{1}+n_{2}}$
$=\frac{3 \times 3+1 \times 5}{4}=\frac{7}{2}$
$\therefore \gamma=1+\frac{2}{f}$
$\Rightarrow \gamma=1+\frac{4}{7}=\frac{11}{7}$