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Question: In a single toss of a fair die, the odds against the event that number 3 or 4 turns up are...

In a single toss of a fair die, the odds against the event that number 3 or 4 turns up are

A

1:2

B

1:3

C

2:1

D

3:1

Answer

2:1

Explanation

Solution

The sample space for a fair die is
S={1,2,3,4,5,6}S = \{1, 2, 3, 4, 5, 6\}.

The favorable outcomes for the event (number 3 or 4 turns up) are
F={3,4}F = \{3, 4\} which is 2 outcomes.

The number of outcomes not favorable is
N=62=4N = 6 - 2 = 4 which is 4 outcomes.

Odds against the event are given by the ratio of non-favorable outcomes to favorable outcomes:
Odds against =42=2:1= \frac{4}{2} = 2:1