Question

$3\,g$ of activated charcoal was added to $50\,mL$ of acetic acid solution ($0.06\,N$) in a flask. After an hour it was filtered and the strength of the filtrate was found to be $0.042\, N$. The amount of acetic acid adsorbed (per gram of charcoal) is

• A. 18 mg
• B. 36 mg
• C. 42 mg
• D. 54 mg

Answer 1

Answer: (A)

18 mg

Answer 2

$CH _{3} COOH (0.06 M )$
$50 \,ml$
$m$. moles $=50 \times 0.06=3$
$m$. moles left $=50 \times 0.042=2.1$
$m$. moles absorbed $=0.9$

mass absorbed $=\frac{0.9 \times 10^{-3} \times 60}{3} \times 10^{3}$
$=\frac{54}{3}=18\, mg$