Answer 1

5-bromo-2-chloroformyl-3-methoxybenzoic acid

Answer 2

The compound is a substituted benzoic acid. According to IUPAC nomenclature rules, the carboxylic acid group (-COOH) has the highest priority. The carbon atom attached to the -COOH group is designated as C1. Numbering proceeds around the benzene ring to give the lowest possible locants to the substituents.

The substituents and their positions are:

• Carboxylic acid (-COOH) at C1.
• Acid chloride (-COCl) at C2 (ortho to -COOH).
• Methoxy group (-OMe) at C3 (meta to -COOH).
• Bromine atom (-Br) at C5 (meta to -COOH).

The parent name is benzoic acid. The substituents are:

• Bromo at position 5.
• Chloroformyl at position 2 (the -COCl group is named as chloroformyl when it is a substituent).
• Methoxy at position 3.

These substituents are arranged alphabetically: bromo, chloroformyl, methoxy. Combining these with the parent name gives the IUPAC name: 5-bromo-2-chloroformyl-3-methoxybenzoic acid.