Question
Mathematics Question on Statistics
3 blue balls and 4 yellow balls are in a box. 3 balls are drawn at random. Let variance and mean be X & Y respectively then value of 3X + 4Y is:
A
5.21
B
8.39
C
7.34
D
6.54
Answer
7.34
Explanation
Solution
The Correct answer is option is (C) : 7.34