QuestionReportMathematics Question on Sequence and series3,a,b,c3, a, b, c3,a,b,c are in Ap and 3,a−1,b+1,c+93, a-1, b+1, c+93,a−1,b+1,c+9 are in GP. Then AM of a,b,ca, b, ca,b,c isAnswerThe answer is 11: