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Question

Chemistry Question on Adsorption

3.63.6 gram of oxygen is adsorbed on 1.2 g1.2\, g of metal powder. What volume of oxygen adsorbed per gram of the adsorbent at 1 atm1\,atm and 273 K273 \,K ?

A

0.19 Lg−10.19\, Lg ^{-1}

B

1 Lg−11\, Lg ^{-1}

C

2.1 Lg−12.1\, Lg ^{-1}

D

None of these

Answer

2.1 Lg−12.1\, Lg ^{-1}

Explanation

Solution

Mass of oxygen adsorbed per gram of metal powder
=3.61.2g=3 g=m=\frac{3.6}{1.2} g =3\, g = m B
y ideal gas equation, PV=nRTP V=n R T
∴V=mRTMP=3×273×0.082132×1atm\therefore V=\frac{ mRT }{ MP }=\frac{3 \times 273 \times 0.0821}{32 \times 1 atm }
=2.1 Lg−1=2.1\, Lg ^{-1}