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Chemistry Question on Thermodynamics

2Zn+O2→2ZnO    ∆Gº=–616J2Zn +O_2→2ZnO \ \ \ \ ∆Gº=–616J
2Zn+S2→2ZnS    ∆Gº=–293J2Zn+S_2→2ZnS\ \ \ \ ∆Gº=–293J
S2+2O2→2SO2    ∆Gº=–408JS_2+2O_2→2SO_2\ \ \ \ ∆Gº=–408J
∆Gº for the following reaction is:∆Gº\ for\ the\ following \ reaction\ is:
2ZnS+3O2→2ZnO+2SO22ZnS+3O_2→2ZnO+2SO_2

A

−731 J-731\ J

B

−1317 J-1317\ J

C

−501 J-501\ J

D

+731 J+731\ J

Answer

−731 J-731\ J

Explanation

Solution

2Zn+O2→2ZnO    ∆Gº=–616J2Zn +O_2→2ZnO \ \ \ \ ∆Gº=–616J ……(1)

2ZnS→2Zn+S2    ∆Gº=+293J2ZnS→2Zn+S_2\ \ \ \ ∆Gº=+293J ..….(2)

S2+2O2→2SO2    ∆Gº=–408JS_2+2O_2→2SO_2\ \ \ \ ∆Gº=–408J .…..(3)

For the reaction
2ZnS+3O2→2ZnO+2SO22ZnS+3O_2→2ZnO+2SO_2

∆Gº∆Gº can be calculated by adding eq (1), eq (2) and eq (3)

∆Gº=−616+293−408∆Gº = -616+293-408

∆Gº=−731 J∆Gº= -731\ J

So, the correct option is (A): −731 J-731\ J