QuestionReportQuestion: \[(2\mathbf{a} + 3\mathbf{b}) \times (5\mathbf{a} + 7\mathbf{b}) =\]...(2a+3b)×(5a+7b)=(2\mathbf{a} + 3\mathbf{b}) \times (5\mathbf{a} + 7\mathbf{b}) =(2a+3b)×(5a+7b)=Aa×b\mathbf{a} \times \mathbf{b}a×bBb×a\mathbf{b} \times \mathbf{a}b×aCa+b\mathbf{a} + \mathbf{b}a+bD7a+10b7\mathbf{a} + 10\mathbf{b}7a+10bAnswerb×a\mathbf{b} \times \mathbf{a}b×aExplanationSolution14(a×b)+15(b×a)=b×a14(\mathbf{a} \times \mathbf{b}) + 15(\mathbf{b} \times \mathbf{a}) = \mathbf{b} \times \mathbf{a}14(a×b)+15(b×a)=b×a.