Question
Question: \(2\log\left( {logtan}\frac{x}{2} \right) + c\)...
2log(logtan2x)+c
A
21log(logtan2x)+c
B
∫cos2x(1−tanx)21dx=
C
tanx−11+c
D
None of these
Answer
∫cos2x(1−tanx)21dx=
Explanation
Solution
21logtan(8π+2x)+c
Putting ∫xx2−116mudx= we get
cos−1x+c.