Question

$2H_2 + O_2 \to 2H_2O$ $2\,g H_2$ and $1\,O_2$ react to form $H_2O$

• A. 3.0 g
• B. 1.125 g
• C. 4.5 g
• D. 2.50 g

Answer 1

Answer: (B)

1.125 g

Answer 2

$\underset{\text{4 R}}{ {2H_{2}}}+ \underset{\text{32 g}}{ {O_{2}}}\to \underset{\text{36 g}}{ {2H_{2}O}}$ Here $O_{2}$ is the limiting reactant $32\, g$ of $O_{2}$ gives $36 \,g$ of water $1\,g$ of $O_{2}$ gives $\frac{36}{32}\,g$ of water $=1.125\,g$ of water