Question
Question: \(2a^{\sqrt{x}}\log_{e}a + c\)...
2axlogea+c
A
2axlogae+c
B
2axlog10a+c
C
2axloga10+c
D
∫1−x8x3dx=
Answer
2axloga10+c
Explanation
Solution
log(cosx+sinx)+c
log(sec2x)+c.
2axlogea+c
2axlogae+c
2axlog10a+c
2axloga10+c
∫1−x8x3dx=
2axloga10+c
log(cosx+sinx)+c
log(sec2x)+c.