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Question

Physics Question on Nuclear physics

82290XαYe+ZβPeQ^{290}_{82}X\stackrel{\alpha}{\rightarrow}Y\stackrel{e^+}{\rightarrow}Z\stackrel{\beta^-}{\rightarrow}P\stackrel{e^-}{\rightarrow}Q
In the nuclear emission stated above, the mass number and atomic number of the product Q respectively, are :

A

280, 81

B

286, 80

C

288, 82

D

286, 81

Answer

286, 81

Explanation

Solution

- After α\alpha decay, mass number reduces by 4, atomic number by 2: 286, 80.

- After β+\beta^+ emission, atomic number reduces by 1: 286, 79.

- After β\beta^- emission, atomic number increases by 1: 286, 80.

- After electron capture, atomic number reduces by 1: 286, 81.