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Question: The molar conductivity of 0.01 M acetic acid at 25 °C is 16.5 $\Omega^{-1}$ cm$^2$ mol$^{-1}$ and it...

The molar conductivity of 0.01 M acetic acid at 25 °C is 16.5 Ω−1\Omega^{-1} cm2^2 mol−1^{-1} and its molar conductivity at zero concentration is 390.7 Ω−1\Omega^{-1} cm2^2 mol−1^{-1}. What is its degree of dissociation?

A

0.0223

B

0.0422

C

0.0642

D

0.0821

Answer

0.0422

Explanation

Solution

The degree of dissociation, α, is given by

α=ΛΛ0\alpha = \frac{\Lambda}{\Lambda^0}

Substituting the given values:

α=16.5390.7≈0.0422\alpha = \frac{16.5}{390.7} \approx 0.0422

Therefore, the degree of dissociation is approximately 0.0422.