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Question: In hypothetical reaction $X_2 + Y_2 \rightarrow 2XY$ Follows the mechanism as given below $X_2 \rig...

In hypothetical reaction X2+Y22XYX_2 + Y_2 \rightarrow 2XY

Follows the mechanism as given below X2X+XX_2 \rightleftharpoons X + X (fast reaction) X+Y2XY+YX + Y_2 \rightarrow XY + Y (slow reaction) X+YXYX + Y \rightarrow XY (fast reaction) The correct statement(s) is/are

A

Order of reaction is 3/2

B

Order of reaction w.r.t. Y2Y_2 is 1.

C

R = k [X]5[Y2][X]^5 [Y_2]

D

Both molecularity and order = 3

Answer

A, B

Explanation

Solution

The reaction mechanism is given as:

  1. X2X+XX_2 \rightleftharpoons X + X (fast reaction)
  2. X+Y2XY+YX + Y_2 \rightarrow XY + Y (slow reaction)
  3. X+YXYX + Y \rightarrow XY (fast reaction)

Step 1: Determine the rate law from the slow step.

The rate of a reaction is determined by its slowest step (rate-determining step). From the slow reaction (Step 2): Rate (R) = kslow[X][Y2]k_{slow} [X] [Y_2]

Step 2: Express the concentration of the intermediate in terms of reactants.

In the rate law, [X][X] is an intermediate species. Its concentration needs to be expressed in terms of the reactant X2X_2. We use the fast equilibrium step (Step 1) for this. For the equilibrium X2X+XX_2 \rightleftharpoons X + X: The equilibrium constant KeqK_{eq} is given by: Keq=[X][X][X2]=[X]2[X2]K_{eq} = \frac{[X][X]}{[X_2]} = \frac{[X]^2}{[X_2]}

Solving for [X][X]: [X]2=Keq[X2][X]^2 = K_{eq} [X_2] [X]=(Keq[X2])1/2=Keq1/2[X2]1/2[X] = (K_{eq} [X_2])^{1/2} = K_{eq}^{1/2} [X_2]^{1/2}

Step 3: Substitute the intermediate concentration into the rate law.

Substitute the expression for [X][X] into the rate law from Step 1: R = kslow(Keq1/2[X2]1/2)[Y2]1k_{slow} (K_{eq}^{1/2} [X_2]^{1/2}) [Y_2]^1 R = (kslowKeq1/2)[X2]1/2[Y2]1(k_{slow} K_{eq}^{1/2}) [X_2]^{1/2} [Y_2]^1

Let the new overall rate constant k=kslowKeq1/2k = k_{slow} K_{eq}^{1/2}. So, the final rate law is: R = k[X2]1/2[Y2]1k [X_2]^{1/2} [Y_2]^1

Step 4: Determine the order of the reaction and evaluate the statements.

  • Order with respect to X2X_2: From the rate law, the exponent of [X2][X_2] is 1/21/2.
  • Order with respect to Y2Y_2: From the rate law, the exponent of [Y2][Y_2] is 11.
  • Overall order of reaction: Sum of the individual orders = 1/2+1=3/21/2 + 1 = 3/2.

Now let's evaluate each statement:

(A) Order of reaction is 3/2 This statement is correct, as the overall order calculated is 3/2.

(B) Order of reaction w.r.t. Y2Y_2 is 1. This statement is correct, as the order with respect to Y2Y_2 is 1.

(C) R = k [X]5[Y2][X]^5 [Y_2] This statement is incorrect. The rate law should be in terms of reactants (X2X_2 and Y2Y_2), not an intermediate (XX), and the exponents are incorrect.

(D) Both molecularity and order = 3 Molecularity is defined for elementary steps, not for the overall complex reaction. For the slow step (X+Y2XY+YX + Y_2 \rightarrow XY + Y), the molecularity is 2. The overall order is 3/2, not 3. Therefore, this statement is incorrect.

Based on the analysis, statements (A) and (B) are correct.