Question

Identify the number of electrons lost by $H_2O$, when it is oxidised to $O_2$ according to following reaction.

$H_2O_{(aq)} + ClO_{(aq)} \longrightarrow ClO_{(aq)} + O_2$

• A. 2 electrons
• B. 1 electron
• C. 4 electrons
• D. No loss of electron

Answer 1

Answer: (C)

4 electrons

Answer 2

The oxidation half–reaction for water to oxygen is given by

$$2H_2O \rightarrow O_2 + 4H^+ + 4e^-$$

This shows that 4 electrons are lost when 2 molecules of water are oxidised.