Question: Figure shows a right angled prism of refractive index $\sqrt{2}$. A plane wave front of monochromati...

Question

Figure shows a right angled prism of refractive index $\sqrt{2}$ . A plane wave front of monochromatic wave ( $\lambda$ = 700 nm) is falling on the prism. The distance between the incident rays is 2 cm. Find the phase difference (in degrees) between the light waves at points A and B after exit from the prism

Answer 1

Solution

The problem describes a scenario with light waves exiting a prism and asks for the phase difference between the waves at points A and B. The key to this problem lies in recognizing that points A and B are depicted on the same wavefront in the diagram.

Understanding Wavefronts:

A wavefront is a line or surface connecting points that are in phase. By definition, all points on the same wavefront have the same phase.

Applying the Concept:

Since points A and B are on the same wavefront after exiting the prism, there is no phase difference between the light waves at these two points. Therefore, the phase difference is 0 degrees.

Conclusion:

The phase difference between the light waves at points A and B is 0 degrees.