Question

$^{27}_{13}AI$ is a stable isotope, $^{29}_{13}AI$ is expected to decay by

• A. $\alpha$-emission
• B. $\beta$-emission
• C. positron emission
• D. proton emission

Answer 1

Answer: (B)

$\beta$-emission

Answer 2

$^{}_{13}AI^{29}$ is neutron rich isotope, will decay by
$\beta$-emission converting some of its neutron into
proton as
\hspace35mm ^{}_{0}n^1 \longrightarrow \, \, ^{}_{-1}\beta^0 + \, ^{}_{1}H^1