Question

25 mL of a solution of barium hydroxide on titration with a 0.1 molar solution of hydrochloric acid gave a titre value of 35 mL. The molarity of barium hydroxide solution was

• A. 0.07
• B. 0.14
• C. 0.28
• D. 0.35

Answer 1

Answer: (A)

0.07

Answer 2

${ Ba(OH)2 + 2HCl -> BaCl2 + 2H2O}$ $\frac{M_1V_1}{n_1} = \frac{M_2V_2}{r_2}$ $[Ba(OH)_2]$ $[HCl]$ $\frac{M_1 \times 25}{1} = \frac{0.1 \times 35}{2}$ $M_1 = \frac{0.1 \times 35}{2 \times 25}$ = 0.07 M.