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Question

Chemistry Question on Some basic concepts of chemistry

25 g of MCl4MCl_4 contains 0.5 mole chlorine then its molecular weight is

A

100 g mol−1mol^{-1}

B

200 g mol−1mol^{-1}

C

150 g mol−1mol^{-1}

D

400 g mol−1mol^{-1}

Answer

200 g mol−1mol^{-1}

Explanation

Solution

0.5 mol chlorine is present in 25 g of MCl4MCl_4. 1 mol chlorine will be present in 50 g of MCl4MCl_4. But MCl4MCl_4 contains 4 moles of chlorine then molecular weight of MCl4MCl_4 = 4 ×\times 50 = 200 g mol−1mol^{-1}