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Question: 25.4g of iodine and \[14.2g\] of chlorine are made to react completely to yield a mixture of \[ICl\]...

25.4g of iodine and 14.2g14.2g of chlorine are made to react completely to yield a mixture of IClICl and ICl3IC{l_3}. Calculate the number of moles of IClICl and ICl3IC{l_3} formed.
A. 0.1mole0.1mole,0.1mole0.1mole
B. 0.1mole0.1mole,0.2mole0.2mole
C. 0.5mole0.5mole,0.5mole0.5mole
D. 0.2mole0.2mole,0.2mole0.2mole

Explanation

Solution

The molarity of a solution is defined as the moles of solute per litre of the solution. Moles present in the substance can be easily calculated by dividing its mass with molar mass. When the iodine and chlorine molecule reacts, it gives IClICl and ICl3IC{l_3} respectively.

Complete step by step answer:
The reaction between iodine and chlorine molecule can be written as,
I2+2Cl2ICl+ICl3......(1){I_2} + 2C{l_2} \to ICl + IC{l_3}......(1)
The mass of the iodine molecule is given as 25.4g25.4g and it is known that the molecular mass of the iodine molecule is 253.80g/mol253.80g/mol. Thus, the mole present in the iodine molecule can be calculated by using the mole formula.
Mole=weightmolecular.weightMole = \dfrac{{weight}}{{molecular.weight}}
Mole=25.4g253.80g/molMole = \dfrac{{25.4g}}{{253.80g/mol}}
Mole=0.1\Rightarrow Mole = 0.1
Thus, 0.1mol0.1mol is present in25.4g25.4g of iodine molecules.
Similarly, the mass of the chlorine molecule is given as 14.2g14.2g and it is known that the molecular mass of the chlorine molecule is 70.9g/mol70.9g/mol. Thus, the mole present in the chlorine molecule can be calculated by using the mole formula.
Mole=14.2g70.9g/molMole = \dfrac{{14.2g}}{{70.9g/mol}}
Mole=0.2\Rightarrow Mole = 0.2
Thus, 0.2mol0.2mol is present in 14.2g14.2gof chlorine.
The mole of IClICl and ICl3IC{l_3} must be the same since the products are in equal concentration as given in reaction (1)
Here, Thus, each 0.1mol0.1mol of iodine molecule consumes two 0.2mol0.2mol of chlorine molecule to give equal mole concentration of mole of IClICl and ICl3IC{l_3}.
Thus, the mole present in IClICl and ICl3IC{l_3} is similar to the mole of iodine molecule since each mole of iodine molecule consumes two moles of chlorine molecule and therefore, chlorine concentration is much not considered.
Therefore, the number of moles of IClICl and ICl3IC{l_3} formed are 0.1mole0.1mole, 0.1mole0.1mole

So, the correct answer is Option A.

Note: Iodine and its components are now widely used in pharmaceuticals. It also acts as antiseptic and disinfectants. It is also used to make polarizing filters for LCDs. Chlorine is mainly used as a disinfectant in water treatment since it kills bacteria present in the water.