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Question: \(24.8\)mole of NaOH is added to 5 litres of water. What will be the pH of the solution?...

24.824.8mole of NaOH is added to 5 litres of water. What will be the pH of the solution?

A

12

B

7

C

2

D

10

Answer

12

Explanation

Solution

: Conc. Of NaOH,=0.055=0.01= \frac{0.05}{5} = 0.01 or 10−2M10^{- 2}M

[OH−]=10−2M\left\lbrack OH^{-} \right\rbrack = 10^{- 2}M

[H+]=Kw[OH−]=10−1410−2=10−12\left\lbrack H^{+} \right\rbrack = \frac{K_{w}}{\left\lbrack OH^{-} \right\rbrack} = \frac{10^{- 14}}{10^{- 2}} = 10^{- 12}

pH=−log⁡[H+]=−log⁡10−12pH = - \log\left\lbrack H^{+} \right\rbrack = - \log{}10^{- 12}= 12