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Question

Physics Question on Alternating current

220 V, 50 Hz AC source is connected to an inductance of 0.2 H and a resistance of 20 ohm in series. What is the current in the circuit:

A

3.33 A

B

33.3 A

C

5 A

D

10 A

Answer

3.33 A

Explanation

Solution

From the formula I=VR2+(ωL)2I=\frac{V}{\sqrt{{{R}^{2}}+{{(\omega L)}^{2}}}} =220(20)2+(2π×50×0.2)2=\frac{220}{\sqrt{{{(20)}^{2}}+{{(2\pi \times 50\times 0.2)}^{2}}}}