Solveeit Logo

Question

Question: 22 gm of \(CO_{2}\) at 27<sup>0</sup>C is mixed with 16 gm of \(O_{2}\) at 37<sup>0</sup>C. The temp...

22 gm of CO2CO_{2} at 270C is mixed with 16 gm of O2O_{2} at 370C. The temperature of the mixture is

A

320C

B

270C

C

370C

D

30.50C

Answer

320C

Explanation

Solution

Let t is the temperature of mixture

Heat gained by CO2CO_{2}= Heat lost by O2O_{2}

μ1Cv1ΔT1=μ2Cv2ΔT2\mu_{1}C_{v_{1}}\Delta T_{1} = \mu_{2}C_{v_{2}}\Delta T_{2}

2244(3R)(t27)=1632(52R)(37t)\frac{22}{44}(3R)(t - 27) = \frac{16}{32}\left( \frac{5}{2}R \right)(37 - t)

3(t27)=52(37t)3(t - 27) = \frac{5}{2}(37 - t)

By solving we get t=32Ct = 32{^\circ}C.