Question

22 g of $CO_{2}$ at 27⁰C is mixed with 16g of $O_{2}$ at 37⁰C. The temperature of the mixture is

• A. 27⁰C
• B. 30.5⁰C
• C. 32⁰C
• D. 37⁰C

Answer 1

Answer: (C)

32⁰C

Answer 2

Heat lost by $CO_{2}$= Heat gained by $O_{2}$

If $µ_{1}\text{and}µ_{2}$are the number of moles of carbon di-oxide and oxygen respectively and $C_{v_{1}}\text{and}C_{v_{2}}$ are the specific heats at constant volume then $µ_{1}C_{v_{1}}\Delta T_{1} = µ_{2}C_{v_{2}}\Delta T_{2}$

⇒ $\frac{22}{44} \times 3R \times (T - 27) = \frac{16}{32} \times \frac{5R}{2}(37 - T)$ ⇒ T = 31.5⁰C ≈ 32⁰C (where T is temperature of mixture)