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Question: If the system of equations $\sin x \cos 2y = (a^2 - 1)^2 + 1$ and $\cos x \sin 2y = (a+1)$ has a sol...

If the system of equations sinxcos2y=(a21)2+1\sin x \cos 2y = (a^2 - 1)^2 + 1 and cosxsin2y=(a+1)\cos x \sin 2y = (a+1) has a solution, then the value of a+2 is ____.

Answer

1

Explanation

Solution

To ensure the RHS of (1) is within the range [1,1][-1,1], we must have (a21)2=0(a^2-1)^2=0 so that a=±1a=\pm1. Testing in (2) shows a=1a=1 gives an impossible value, so a=1a=-1 is valid. Hence, a+2=1a+2=1.