Solveeit Logo

Question

Question: \(20mL\) of \(0.1N\) \(HCl\) is mixed with \(20mL\) of\(0.1N\) \(KOH\). The \(pH\) of the solution w...

20mL20mL of 0.1N0.1N HClHCl is mixed with 20mL20mL of0.1N0.1N KOHKOH. The pHpH of the solution would be:
A: 00
B: 77
C: 22
D: 99

Explanation

Solution

pHpH is the measure of H+{H^ + }ions released by a substance when dissolved in water. On the basis of pHpH it is defined whether the substance is acidic or basic. Species having pHpH from 00 to 77are acidic and substances having pHpH from 77 to 1414 are basic in nature.
Formula used: pH=log[H+]pH = - \log \left[ {{H^ + }} \right]
Where [H+]\left[ {{H^ + }} \right] is concentration of H+{H^ + } ions, which will be given by the following formula.
[H+]=N×V\left[ {{H^ + }} \right] = N \times V Or [OH]=N×V\left[ {O{H^ - }} \right] = N \times V
Where NN is normality and VV is volume

Complete answer:
In case of HClHCl [H+]=0.1×20ml=2mM\left[ {{H^ + }} \right] = 0.1 \times 20ml = 2mM
In case of KOHKOH [OH]=0.1×20ml=2mM\left[ {O{H^ - }} \right] = 0.1 \times 20ml = 2mM
As seen there are no extra [H+]\left[ {{H^ + }} \right] ions in the solution as they are completely neutralized by equal concentration of [OH]\left[ {O{H^ - }} \right] coming from KOHKOH. So our resulting solution will be neutral and we know neutral solution is having pH=7pH = 7

Therefore our answer to this question will be option B that is 77 .

Additional information:
The concentration of a solution is also called molarity. Molarity is the measure of the number of moles present per liter of solution. It can be calculated as:
Molarity =m×1000M×V = \dfrac{{m \times 1000}}{{M \times V}} where mmis given mass of substance, MM is molar mass of substance and VV is volume of solution. Units of molarity aremolL1mol{L^{ - 1}} .
Normality (N)\left( N \right) is also known as the equivalent concentration of a solution. Normality is a measure of gram equivalent weight per liter of solution. The equivalent weight of an element is its gram atomic weight divided by its valence. Gram atomic weight is also known as atomic mass. The normality of a solution can be calculated as:
Normality=mE×VNormality = \dfrac{m}{{E \times V}} Wheremm weight of solute in grams, EE is equivalent weight of substance and VV is volume of solution in liter.

Note:
pHpHof any solution is the degree to measure whether the solution is acidic, basic or neutral.
For acidic solution 0<pH<70 < pH < 7
For neutral solution pH=7pH = 7
For basic solution 7<pH<147 < pH < 14