Question: 200 V ac source is fed to series LCR circuit having $X_{L}$=50$\Omega$,and R= 25$\Omega$. Pote...

Question

200 V ac source is fed to series LCR circuit having $X_{L}$ =50 $\Omega$ ,and R= 25 $\Omega$ . Potential drop across the inductor is

Answer 1

: Here, $V_{rms} = 200V$

$X_{L} = 50\Omega,X_{C} = 50\Omega,R = 25\Omega$

Impedance of the circuit,

$I_{rms} = \frac{V_{rms}}{Z} = \frac{200V}{25\Omega} = 8A$

Voltage drop across the inductor is

$V_{L} = I_{rms}X_{L} = 8A \times 50\Omega = 400V$

Question: 200 V ac source is fed to series LCR circuit having \(X_{L}\)=50\(\Omega\),and R= 25\(\Omega\). Pote...