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Question: 200 ml of 1 M \[{{H}_{2}}S{{O}_{4}}\], 300 ml of 3 M HCl and 100 ml of 2 M HCl are mixed and made up...

200 ml of 1 M H2SO4{{H}_{2}}S{{O}_{4}}, 300 ml of 3 M HCl and 100 ml of 2 M HCl are mixed and made up to 1 litre. The proton concentration in the resulting solution is:
A) 1.25 M
B) 1.5 M
C) 2.5 M
D) 0.75 M

Explanation

Solution

Hint: The molarity of a mixed solution can be given by
Mmixture=M1V1+M2V2+M3V3V1+V2+V3{{M}_{mixture}}=\dfrac{{{M}_{1}}{{V}_{1}}+{{M}_{2}}{{V}_{2}}+{{M}_{3}}{{V}_{3}}}{{{V}_{1}}+{{V}_{2}}+{{V}_{3}}}
The numerator here is just a total (sum) of all the moles of solute and the denominator is a total (sum) of all the volumes.

Complete step by step solution:

- Molarity is the number of moles of a solute per litre of a solution. Molarity is also known as the molar concentration of a solution.
- Concentration in molarity (mol/L or M) is often depicted with square brackets around the solute of interest. For example, the concentration of hydrogen ion can be written as [H+{{H}^{+}}]
By applying the molarity mixture formula
We can see that the 1M H2SO4{{H}_{2}}S{{O}_{4}}, number of H+{{H}^{+}}ions are two in number and the volume is 0.2L.
Therefore, the number moles of H+{{H}^{+}}in 1M of H2SO4{{H}_{2}}S{{O}_{4}} is, M1V1{{M}_{1}}{{V}_{1}} = 2 × 0.2L × 1mol/L = 0.4

Similarly, in 3M of HCl, the number of H+{{H}^{+}} is one and the volume is 0.3L.
Thus, the number of moles of H+{{H}^{+}}in 3M of HCl is, M2V2{{M}_{2}}{{V}_{2}} = 0.3L × 3mol/L = 0.9
In 2M of HCl, the number of H+{{H}^{+}}ions is one and the volume is 0.2L.
The total number of moles of H+{{H}^{+}}ions in 2M of HCl is, M3V3{{M}_{3}}{{V}_{3}} = 0.1L × 2mol/L = 0.2

So, total moles of H+{{H}^{+}}ions, M1V1+M2V2+M3V{{M}_{1}}{{V}_{1}}+{{M}_{2}}{{V}_{2}}+{{M}_{3}}V = 0.4 + 0.9 + 0.2
= 1.5

We have been given here that the total volume is, V1+V2+V3{{V}_{1}}+{{V}_{2}}+{{V}_{3}}= 1 L.
From using the above formula in hint,
Mmixture=M1V1+M2V2+M3V3V1+V2+V3{{M}_{mixture}}=\dfrac{{{M}_{1}}{{V}_{1}}+{{M}_{2}}{{V}_{2}}+{{M}_{3}}{{V}_{3}}}{{{V}_{1}}+{{V}_{2}}+{{V}_{3}}}
Mmixture=1.5mole1L{{M}_{mixture}}=\dfrac{1.5\,mole}{1\,L}

So, [H+{{H}^{+}}]= 1.5mol/L

Therefore, we can say that the correct answer is (b).

Note: Don't get confused between molarity and molality, molality is the number of moles of solute present in per kilogram of solvent. Its SI unit is mol/kg and a solution with molality 2mol/kg is said to be 2 m.