(({20 mL})) of (({ 0.5, N, HCl})) and (({35, mL})) of (({0.1... | Chemistry | SolveeIt

Question

$\({20 mL}$ ) of $\({ 0.5\, N\, HCl}$ ) and $\({35\, mL}$ ) of $\({0.1 \,N\, NaOH}$ ) are mixed. The resulting solution will

be neutral

be basic

turn phenolphthalein solution pink

turn methyl orange red.

Answer

turn methyl orange red.

Explanation

Solution

$\({20 \, mL}$ ) of $\({0.5\, N\, HCl = 20 \times 0.5\, milli e}$ ) $\({= 10\, milli\, e \,of \,HCl}$ ) $\({35\, mL }$ ) of $\({ 0.1\, N \, NaOH = 35 \times 0.1\, milli \, e}$ ) $\({= 3.5\, milli \, e \, of \, NaOH.}$ ) Thus, $\({3.5\, milli \, e \, of \, NaOH }$ ) will neutralize ${3.5 milli \, e\, of \, HCl (10 - 3.5) = 6.5 \, milli \, e \, of \, HCl}$ will be left. Therefore, solution will be acidic and it will turn methyl orange red.

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