Question

20 guests have to sit half on each side of a long table. Three particular guests desire to sit on a particular side, five others on the other side. In how many ways, the seating arrangement can be made?

• A. $10!\times\frac{10!}{7!}\times\frac{10!}{5!}$
• B. $12!\times\frac{10!}{7!}\times\frac{10!}{5!}$
• C. 20!×13!×15!
• D. $20!\times\frac{7!}{3!}$
• E. $20!\times\frac{10!}{7!}$

Answer 1

Answer: (B)

$12!\times\frac{10!}{7!}\times\frac{10!}{5!}$

Answer 2

The correct option is (B): $12!\times\frac{10!}{7!}\times\frac{10!}{5!}$