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Question

Question: Figure shows two dipole moments parallel to each other and placed at a distance x apart x is very la...

Figure shows two dipole moments parallel to each other and placed at a distance x apart x is very large. Then:

A

they will repel each other

B

they will attract each other

C

force of interaction is of magnitude of 3P1P24πϵ0x4\frac{3P_1P_2}{4\pi\epsilon_0x^4}

D

force of interaction is of magnitude of 6P1P24πϵ0x4\frac{6P_1P_2}{4\pi\epsilon_0x^4}

Answer

Options (A) and (C).

Explanation

Solution

For two dipoles with moments P1P_1 and P2P_2 both pointing upward and arranged side-by-side (separated horizontally by a large distance xx), the interaction energy is given by

U=14πϵ0P1P2x3.U = \frac{1}{4\pi\epsilon_0} \frac{P_1P_2}{x^3}.

Taking the derivative with respect to xx, we get the force:

F=dUdx=3P1P24πϵ0x4.F = -\frac{dU}{dx} = \frac{3P_1P_2}{4\pi\epsilon_0x^4}.

Since the force is positive (repulsive) along the line joining them, the dipoles repel each other.