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Question: 2 moles of *PCl*<sub>5</sub> were heated in a closed vessel of 2 litre capacity. At equilibrium, 40%...

2 moles of PCl5 were heated in a closed vessel of 2 litre capacity. At equilibrium, 40% of PCl5 is dissociated into PCl3 and Cl2. The value of equilibrium constant is

A

0.266

B

0.53

C

2.66

D

5.3

Answer

0.266

Explanation

Solution

At start, PCl52\underset{2}{PCl_{5}}PCl30+Cl20\underset{0}{PCl_{3}} + \underset{0}{Cl_{2}}

At equilibrium. 2×60100\frac{2 \times 60}{100} 2×40100\frac{2 \times 40}{100} 2×40100\frac{2 \times 40}{100}

Volume of cantainer = 2 litre

\therefore Kc=2×40100×2×2×40100×22×60100×2K_{c} = \frac{\frac{2 \times 40}{100 \times 2} \times \frac{2 \times 40}{100 \times 2}}{\frac{2 \times 60}{100 \times 2}} = 0.266