Question

For the figure shown, what is the ratio of the charges $q_2/q_1$, where the figure shown has a representation of the field lines in the space near the charges:

• A. -3/2
• B. -2/3
• C. 2/3
• D. 3/2

Answer 1

Answer: (B)

Option (B) $-2/3$

Answer 2

Since the number of field lines is proportional to the magnitude of the charge, we have:

$$\frac{|q_2|}{q_1}=\frac{4}{6}=\frac{2}{3}$$

Because the field lines originate from a positive charge (q₁) and terminate on a negative charge (q₂), the sign of q₂ is negative relative to q₁. Thus:

$$\frac{q_2}{q_1}=-\frac{2}{3}$$

Explanation (minimal):
Field lines proportionality gives: $|q_2|/q_1 = 4/6 = 2/3$. With opposite signs, $q_2/q_1 = -2/3$.