Question

2-Chlorobutane on treatment with alcoholic KOH/D gives mainly

• A. 2-Butene
• B. 1-Butene
• C. 2-Butanol
• D. 1-Butyne

Answer 1

Answer: (A)

2-Butene

Answer 2

It is E2 reaction [anti elimination].

$\overset{\quad Alc.KOH\quad}{\rightarrow}$CH3—CH=CH—CH3