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Question: An ellipsoidal gaussion surface with semi major axis a and semi-minor axis b is shown in figure. An ...

An ellipsoidal gaussion surface with semi major axis a and semi-minor axis b is shown in figure. An electric field E=C(xi^+yj^+zk^)(x2+y2+z2)3/2\vec{E} = \frac{C(x\hat{i}+y\hat{j}+z\hat{k})}{(x^2 + y^2 + z^2)^{3/2}} exist in space.

A

Net flux through the gaussion surface is 4πC4\pi C

B

Net charge enclosed by gaussion surface is 4πCϵ04\pi C\epsilon_0

C

If given surface is a conductor electric potential at all its inside points may be constant for given field function

D

If given surface is a conductor electric field at all its inside points may be constant for given field function

Answer

A, B, C, D

Explanation

Solution

The electric field is E=Crr3\vec{E} = C\frac{\vec{r}}{r^3}, which is the field of a point charge q=4πϵ0Cq = 4\pi\epsilon_0 C at the origin.

(A) By Gauss's law, ΦE=Qenclosedϵ0=4πϵ0Cϵ0=4πC\Phi_E = \frac{Q_{enclosed}}{\epsilon_0} = \frac{4\pi\epsilon_0 C}{\epsilon_0} = 4\pi C.

(B) The net charge enclosed is q=4πϵ0Cq = 4\pi\epsilon_0 C.

(C) For a conductor in electrostatic equilibrium, Einside=0\vec{E}_{inside} = 0. If E=0\vec{E}=0, then the potential is constant.

(D) Einside=0\vec{E}_{inside} = 0, which is a constant value.