Solveeit Logo

Question

Question: \(2.18{\text{g}}\) of an organic compound containing sulfur produces \(1.02{\text{g}}\) of \({\text{...

2.18g2.18{\text{g}} of an organic compound containing sulfur produces 1.02g1.02{\text{g}} of BaSO4{\text{BaS}}{{\text{O}}_4}. The percentage of sulfur in the compound is:
A. 7.26%7.26\%
B. 8.98%8.98\%
C. 10%10\%
D. 6.42%6.42\%

Explanation

Solution

The percentage composition of a component in a compound is the percentage of the total mass of the compound that is due to the component. By finding each element’s percentage composition in a compound, we can calculate the formula mass and empirical mass of the compound.

Complete step by step answer:
Percentage composition is the percentage by mass of each element in a compound.
It is given that amount of organic compound, morg=2.18g{{\text{m}}_{{\text{org}}}} = 2.18{\text{g}}
Amount of BaSO4{\text{BaS}}{{\text{O}}_4},mBaSO4=1.02g{{\text{m}}_{{\text{BaS}}{{\text{O}}_4}}} = 1.02{\text{g}}
We know that atomic mass of sulfur, MS=32u{{\text{M}}_{\text{S}}} = 32{\text{u}}
Molecular weight of BaSO4{\text{BaS}}{{\text{O}}_4}, MBaSO4=233u{{\text{M}}_{{\text{BaS}}{{\text{O}}_4}}} = 233{\text{u}}
Thus the percentage of sulfur can be calculated from these values.
This is obtained by dividing the amount of sulfur in the compound by molar mass.
i.e. %S=MSMBaSO4÷morgmBaSO4\% {\text{S}} = \dfrac{{{{\text{M}}_{\text{S}}}}}{{{{\text{M}}_{{\text{BaS}}{{\text{O}}_4}}}}} \div \dfrac{{{{\text{m}}_{{\text{org}}}}}}{{{{\text{m}}_{{\text{BaS}}{{\text{O}}_4}}}}}
Taking reciprocal, we get
The percentage of sulfur, %S = MSMBaSO4×mBaSO4morg×100\% {\text{S = }}\dfrac{{{{\text{M}}_{\text{S}}}}}{{{{\text{M}}_{{\text{BaS}}{{\text{O}}_4}}}}} \times \dfrac{{{{\text{m}}_{{\text{BaS}}{{\text{O}}_4}}}}}{{{{\text{m}}_{{\text{org}}}}}} \times 100
Substituting the values, we get
%S = 32233×1.022.18×100\% {\text{S = }}\dfrac{{32}}{{233}} \times \dfrac{{1.02}}{{2.18}} \times 100
Simplifying,
%S=0.1373×0.4678×100=6.42%\% {\text{S}} = 0.1373 \times 0.4678 \times 100 = 6.42\%
Hence the percentage of sulfur in the compound is 6.42%6.42\%
So option D is correct.

Additional information:
Molecular formula tells exactly how many of each atom are in the molecule and empirical formula tells the ratio of atoms in a molecule. Empirical formula is the simplest ratio of elements in a chemical formula. Both of them can be calculated from the percentage composition of elements.

Note:
The steps involved in finding the percentage composition of a component in a compound are:
-Find the molar mass of the compound by adding up the atomic masses of each element.
-Calculate the mass due to the component.
-Divide the mass due to the component by total molar mass of the compound and multiply by 100100.