Question
Question: \(2.18{\text{g}}\) of an organic compound containing sulfur produces \(1.02{\text{g}}\) of \({\text{...
2.18g of an organic compound containing sulfur produces 1.02g of BaSO4. The percentage of sulfur in the compound is:
A. 7.26%
B. 8.98%
C. 10%
D. 6.42%
Solution
The percentage composition of a component in a compound is the percentage of the total mass of the compound that is due to the component. By finding each element’s percentage composition in a compound, we can calculate the formula mass and empirical mass of the compound.
Complete step by step answer:
Percentage composition is the percentage by mass of each element in a compound.
It is given that amount of organic compound, morg=2.18g
Amount of BaSO4,mBaSO4=1.02g
We know that atomic mass of sulfur, MS=32u
Molecular weight of BaSO4, MBaSO4=233u
Thus the percentage of sulfur can be calculated from these values.
This is obtained by dividing the amount of sulfur in the compound by molar mass.
i.e. %S=MBaSO4MS÷mBaSO4morg
Taking reciprocal, we get
The percentage of sulfur, %S = MBaSO4MS×morgmBaSO4×100
Substituting the values, we get
%S = 23332×2.181.02×100
Simplifying,
%S=0.1373×0.4678×100=6.42%
Hence the percentage of sulfur in the compound is 6.42%
So option D is correct.
Additional information:
Molecular formula tells exactly how many of each atom are in the molecule and empirical formula tells the ratio of atoms in a molecule. Empirical formula is the simplest ratio of elements in a chemical formula. Both of them can be calculated from the percentage composition of elements.
Note:
The steps involved in finding the percentage composition of a component in a compound are:
-Find the molar mass of the compound by adding up the atomic masses of each element.
-Calculate the mass due to the component.
-Divide the mass due to the component by total molar mass of the compound and multiply by 100.